relative pathname

用法例句

This paper presents a method based on node relative path for extracting XML Schema.

结合XML文档树结构提出了一种基于节点相对路径的模式抽取算法,通过使用SAX解析器对XML文档进行一遍扫描,提取出XML文档节点及其相对路径来实现XML文档模式的抽取。

"Path name %1 is not a valid relative path name. Enter a valid relative path name.

"路径名 %1 不是一个有效的相对路径名。输入一个有效的相对路径名。

The installation folder name you specified is not valid. The folder name must specify a relative path.

指定的安装文件夹名无效。必须在文件夹名中指定相对路径。

Path %1 is not a valid absolute path name. Enter a valid absolute path name.

路径 %1 不是一个有效的绝对路径名。请输入一个有效的绝对路径名。

The URL parameter may be either a relative or complete URL.

URL可以是绝对路径或是相对的路径。

A location path can be absolute or relative.

区域路径表达式可以是绝对路径，也可以是相对路径。

Illegal local path: A local path name must be absolute and in the form Drive:AbsolutePath

非法的本地路径: 本地路径名称必须是绝对路径并且格式为“驱动器:绝对路径”

Invalid project path specified. Project paths cannot contain relative paths.

指定的项目路径无效。项目路径不能包含相对路径。

Same key name specified multiply in object path.

对象路径里有多个指定的同键名称。

Choose the path and file name for the object you have selected.

为选定的对象选择路径和文件名称。

Composer can't open the URL 'XX'. You must enter an absolute URL or an absolute pathname.

编写器无法打开 URL'XX'。必须输入绝对路径 URL 或绝对路径名。

Relative Path : The path relative to the virtual directory to which the primary project output will be copied.

相对路径:相对于主项目输出将复制到的虚拟目录的路径。

{0} {1} contains a relative path {2}. Relative paths are not allowed in alternate access settings.

{0} {1} 包含相对路径 {2}。在备用访问设置中不允许使用相对路径。

The path to the folder is not valid for the %0 property. Check the path name and try again.

该文件夹路径对 %0 属性无效。请检查路径名并重试。

All assembly references should use relative path.

所有程序集应该使用相对路径引用。

A Method for XML Schema Extraction Based on Node Relative Path

基于节点相对路径的XML模式抽取算法

The volume name or path is not valid for this server. Make sure you are specifying an accurate name or path, and then try again.

卷名或路径对此服务器无效。请确认指定了正确的名称或路径，然后再试一次。

Each increment of work along one path is matched by a corresponding increment on the other, so the sums must be equal.

沿一路径的功的每一增量与沿另一路径相对应的功增量相同，故其总和亦必相等。

The classical path would then correspond to a ray as in optics.

所以经典路径就与光学中的光线相对应。